What is the asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) ?

The asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) is Vertical: x= 4/3 ,Horizontal: y= 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4)

asymptotes

f (x) = \frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4}

Vertical : x = \frac{4}{3}, Horizontal : y = \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4} : x = \frac{4}{3}

Horizontal Asymptotes of

\frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4} : y = \frac{1}{3}

Slant Asymptotes of

\frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4} :

None

Vertical : x = \frac{4}{3}, Horizontal : y = \frac{1}{3}

y = - 10 x

\frac{- 4}{x ^{2}} + 1

y = 2 x - 1

f (x) = lo g_{5} (- 2 x^{4})

4 x^{\frac{1}{3}} - x^{\frac{4}{3}}

What is the asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) ?
The asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) is Vertical: x= 4/3 ,Horizontal: y= 1/3