What is the domain of \sqrt[4]{x^4-16} ?

The domain of \sqrt[4]{x^4-16} is x = 2

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domain of \sqrt[4]{x^4-16}

domain

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

(m, n), (0, 0)

(6, - 5), (3, 1)

f (x) = 2 x^{3} - 3 x^{2} - 72 x + 3

lo g_{3} (x + 6)

f (x) = \frac{6 ^{x}}{3}

What is the domain of \sqrt[4]{x^4-16} ?
The domain of \sqrt[4]{x^4-16} is x<=-2\lor x>= 2