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Popular >

range of-(x-4)^2+17

Solution

range

- (x - 4)^{2} + 17

Solution

f (x) \leq 17

+1

Interval Notation

(- \infty, 17]

Solution steps

Vertex of

- (x - 4)^{2} + 17 :

Maximum

(4, 17)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (4, 17)

f (x) \leq 17

Popular Examples

inverse of y=-8x+16 inverse

y = - 8 x + 16

inverse of f(x)=x^2-x,x>= 1/2 inverse

f (x) = x^{2} - x, x \geq \frac{1}{2}

inverse of f(x)=(x-2)/7+8 inverse

f (x) = \frac{x - 2}{7} + 8

domain of y=sqrt(9-x^2)domain

y = 9 - x^{2}

range of f(x)=(x-2)^2+2 range

f (x) = (x - 2)^{2} + 2

Frequently Asked Questions (FAQ)

What is the range of-(x-4)^2+17 ?
The range of-(x-4)^2+17 is f(x)<= 17