What is the inverse of g(t)=(7-9t)^{5/2} ?

The inverse of g(t)=(7-9t)^{5/2} is -(t^{2/5}-7)/9

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inverse of g(t)=(7-9t)^{5/2}

inverse

g (t) = (7 - 9 t)^{\frac{5}{2}}

- \frac{t ^{\frac{2}{5}} - 7}{9}

Solution steps

y = (7 - 9 t)^{\frac{5}{2}}

Replace

t

with

y

t = (7 - 9 y)^{\frac{5}{2}}

Solve for

y, t = (7 - 9 y)^{\frac{5}{2}}

- \frac{t ^{\frac{2}{5}} - 7}{9}

f (x) = \frac{- 9 x + 8}{- 12 x + 11}

9 - 3^{x}

f (x) = \frac{x}{1 - ln ( x - 9 )}

f (x) = \frac{x + 1}{x}

f (x) = \frac{x}{x ^{2} - 25}

What is the inverse of g(t)=(7-9t)^{5/2} ?
The inverse of g(t)=(7-9t)^{5/2} is -(t^{2/5}-7)/9