What is the perpendicular y+3=-1/2 (x-10) ?

The perpendicular y+3=-1/2 (x-10) is y=2x+b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y+3=-1/2 (x-10)

perpendicular

y + 3 = - \frac{1}{2} (x - 10)

y = 2 x + b

Solution steps

Find the slope of

y + 3 = - \frac{1}{2} (x - 10) : m = - \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = 2

Line with slope m=

2 : y = 2 x + b

y = 2 x + b

f (x) = \frac{9}{x - 6}

f (x) = x^{2} (96 - x)

4 x^{2} + 20

(7, - 6), (- 5, 8)

f (x) = x^{2} (7 - x)^{3}

What is the perpendicular y+3=-1/2 (x-10) ?
The perpendicular y+3=-1/2 (x-10) is y=2x+b