What is the critical (x^2-7)^3 ?

The critical (x^2-7)^3 is x=-sqrt(7),x=0,x=sqrt(7)

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critical (x^2-7)^3

critical points

(x^{2} - 7)^{3}

x = - 7, x = 0, x = 7

Solution steps

(x^{2} - 7)^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 7, x = 0, x = 7

Identify critical points not in

f (x)

domain

Domain of

(x^{2} - 7)^{3} : - \infty < x < \infty

All critical points are in domain

x = - 7, x = 0, x = 7

f (x) = \frac{5}{4 x - 8}

y = x^{2} + 6 x + 9

\frac{x ^{2} - 16}{3 x ^{2}}

f (x) = t 4 - t

x^{2} - 2

What is the critical (x^2-7)^3 ?
The critical (x^2-7)^3 is x=-sqrt(7),x=0,x=sqrt(7)