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Popular >

range of f(x)=x^2+2x+9

Solution

range

f (x) = x^{2} + 2 x + 9

Solution

f (x) \geq 8

+1

Interval Notation

[8, \infty)

Solution steps

Vertex of

x^{2} + 2 x + 9 :

Minimum

(- 1, 8)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 1, 8)

f (x) \geq 8

Popular Examples

domain of (64)/(x^2)+81 domain

\frac{64}{x ^{2}} + 81

inverse of y=sqrt(x-4)inverse

y = x - 4

inverse of 1500 inverse

1500

domain of x/(sqrt(x^2+7))domain

\frac{x}{x ^{2} + 7}

inverse of y=\sqrt[4]{x}inverse

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+2x+9 ?
The range of f(x)=x^2+2x+9 is f(x)>= 8