What is the extreme f(x)=x^3-5x^2-8x+4 ?

The extreme f(x)=x^3-5x^2-8x+4 is Maximum(-2/3 , 184/27),Minimum(4,-44)

Popular >

extreme f(x)=x^3-5x^2-8x+4

extreme points

f (x) = x^{3} - 5 x^{2} - 8 x + 4

Maximum (- \frac{2}{3}, \frac{184}{27}), Minimum (4, - 44)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 5 x^{2} - 8 x + 4 : \frac{184}{27}

Maximum (- \frac{2}{3}, \frac{184}{27})

Plug

x = 4

into

x^{3} - 5 x^{2} - 8 x + 4 : - 44

Minimum (4, - 44)

Maximum (- \frac{2}{3}, \frac{184}{27}), Minimum (4, - 44)

f (x) = \frac{x ( x + 3 )}{x ^{2} + x - 6}

\frac{- x - 3}{x + 2}

f (x) = 5 - 3 x

- \frac{1}{2 6 - x}

f (x) = 9 x^{2} - x^{3} - 3

What is the extreme f(x)=x^3-5x^2-8x+4 ?
The extreme f(x)=x^3-5x^2-8x+4 is Maximum(-2/3 , 184/27),Minimum(4,-44)