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Popular >

range of 6x-x^2+7

Solution

range

6 x - x^{2} + 7

Solution

f (x) \leq 16

+1

Interval Notation

(- \infty, 16]

Solution steps

Vertex of

6 x - x^{2} + 7 :

Maximum

(3, 16)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (3, 16)

f (x) \leq 16

Popular Examples

slope of y= 3/5 slope

y = \frac{3}{5}

asymptotes of f(x)= x/(x^2+16)asymptotes

f (x) = \frac{x}{x ^{2} + 16}

inverse of f(x)=log_{6}(4x)+log_{6}(3)inverse

f (x) = lo g_{6} (4 x) + lo g_{6} (3)

inverse of f(x)=(x^5)/5 inverse

f (x) = \frac{x ^{5}}{5}

domain of f(x)=(sqrt(3+x))/(2-x)domain

f (x) = \frac{3 + x}{2 - x}

Frequently Asked Questions (FAQ)

What is the range of 6x-x^2+7 ?
The range of 6x-x^2+7 is f(x)<= 16