What is the domain of f(x)=(2x+1)/(x-1) ?

The domain of f(x)=(2x+1)/(x-1) is x 1

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domain of f(x)=(2x+1)/(x-1)

domain

f (x) = \frac{2 x + 1}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = (x^{2} - 1)^{2} - 1

f (x) = \frac{1}{2} x^{2}

(7.2) (9.16)

f (x) = 3 x^{5} - 5 x^{3}

\frac{2 x ^{3}}{3} - x^{2} + \frac{x}{2} + \frac{1}{3}

What is the domain of f(x)=(2x+1)/(x-1) ?
The domain of f(x)=(2x+1)/(x-1) is x<1\lor x>1