What is the perpendicular 3x+2y=-7,(1,1) ?

The perpendicular 3x+2y=-7,(1,1) is y= 2/3 x+1/3

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perpendicular 3x+2y=-7,(1,1)

perpendicular

3 x + 2 y = - 7, (1, 1)

y = \frac{2}{3} x + \frac{1}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

3 x + 2 y = - 7

that passes through

(1, 1)

Find the slope of

3 x + 2 y = - 7 : m = - \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(1, 1) : y = \frac{2}{3} x + \frac{1}{3}

y = \frac{2}{3} x + \frac{1}{3}

- \frac{3}{x}

y = - \frac{1}{3} sin (\frac{5 x}{4})

f (x) = \frac{1}{x} + 1

f (x) = \frac{x ^{2}}{x + 2}

f (x) = 5 x - 1

What is the perpendicular 3x+2y=-7,(1,1) ?
The perpendicular 3x+2y=-7,(1,1) is y= 2/3 x+1/3