What is the critical f(x)=x^3-x ?

The critical f(x)=x^3-x is x=-1/(sqrt(3)),x= 1/(sqrt(3))

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critical f(x)=x^3-x

critical points

f (x) = x^{3} - x

x = - \frac{1}{3}, x = \frac{1}{3}

Solution steps

x^{3} - x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{3}, x = \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} - x : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{3}, x = \frac{1}{3}

\frac{1}{4 - x ^{2}}

y = x^{3} - 4 x

f (x) = 3 (x + 8)^{7}

f (x) = \frac{x + 2}{x ^{2} + 2 x - 8}

f (x) = - 2 (\frac{1}{4})^{x - 3}

What is the critical f(x)=x^3-x ?
The critical f(x)=x^3-x is x=-1/(sqrt(3)),x= 1/(sqrt(3))