What is the domain of f(t)=\sqrt[3]{t+6} ?

The domain of f(t)=\sqrt[3]{t+6} is -infinity <t<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(t)=\sqrt[3]{t+6}

domain

- \infty < t < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

f (x) = \frac{2 x}{x - 2}

f (x) = \frac{x + 3}{x - 1}

x^{3} - 2 x^{2} + x + 8

y = x - 2

f (x) = x^{3} - 6 x^{2} - 96 x

What is the domain of f(t)=\sqrt[3]{t+6} ?
The domain of f(t)=\sqrt[3]{t+6} is -infinity <t<infinity