What is the critical f(x)=40x-4x^2 ?

The critical f(x)=40x-4x^2 is x=5

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critical f(x)=40x-4x^2

critical points

f (x) = 40 x - 4 x^{2}

x = 5

Solution steps

40 x - 4 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 5

Identify critical points not in

f (x)

domain

Domain of

40 x - 4 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 5

x^{3} - 4 x

f (x) = \frac{30}{7} - \frac{3}{7} x

x - 5 x^{\frac{1}{5}}

x - 2 y = 5

f (x) = 81000 - 7000 x