What is the domain of (2x^2-8x)/(x^2-7x+12) ?

The domain of (2x^2-8x)/(x^2-7x+12) is x 4

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domain of (2x^2-8x)/(x^2-7x+12)

domain

\frac{2 x ^{2} - 8 x}{x ^{2} - 7 x + 12}

x < 3 or 3 < x < 4 or x > 4

Interval Notation

(- \infty, 3) \cup (3, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = 3

The function domain

x < 3 or 3 < x < 4 or x > 4

y = 4 - x^{2}

f (x) = \frac{5 - 3 x}{7 - 4 x}

sin (x)

f (x) = 3 csc (x + \frac{π}{2})

5 x + 6 y = 42

What is the domain of (2x^2-8x)/(x^2-7x+12) ?
The domain of (2x^2-8x)/(x^2-7x+12) is x<3\lor 3<x<4\lor x>4