What is the extreme f(x)=x^3-3x^2-24x-4 ?

The extreme f(x)=x^3-3x^2-24x-4 is Maximum(-2,24),Minimum(4,-84)

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extreme f(x)=x^3-3x^2-24x-4

extreme points

f (x) = x^{3} - 3 x^{2} - 24 x - 4

Maximum (- 2, 24), Minimum (4, - 84)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 2

into

x^{3} - 3 x^{2} - 24 x - 4 : 24

Maximum (- 2, 24)

Plug

x = 4

into

x^{3} - 3 x^{2} - 24 x - 4 : - 84

Minimum (4, - 84)

Maximum (- 2, 24), Minimum (4, - 84)

(- 4, 5), (2, - 3)

\frac{1}{x + 10}

f (x) = \frac{2}{3} x - 4

x + 4 y = 1

f (x) = - 4 - x^{2}

What is the extreme f(x)=x^3-3x^2-24x-4 ?
The extreme f(x)=x^3-3x^2-24x-4 is Maximum(-2,24),Minimum(4,-84)