What is the domain of f(x)= 1/(sqrt(4-x^2)) ?

The domain of f(x)= 1/(sqrt(4-x^2)) is -2<x<2

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domain of f(x)= 1/(sqrt(4-x^2))

domain

f (x) = \frac{1}{4 - x ^{2}}

- 2 < x < 2

Interval Notation

(- 2, 2)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

- 2 < x < 2

y = - x^{2} + 10 x - 23

f (x) = x^{2} - 9 x + 20 - ln (x - 3)

f (x) = - 2 x - 5

f (x) = (1.7) (3.5)

\frac{2 x ^{2} + 2 x - 12}{x ^{2} + x}

What is the domain of f(x)= 1/(sqrt(4-x^2)) ?
The domain of f(x)= 1/(sqrt(4-x^2)) is -2<x<2