What is the domain of f(x)= 2/(sqrt(9+4x)) ?

The domain of f(x)= 2/(sqrt(9+4x)) is x>-9/4

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domain of f(x)= 2/(sqrt(9+4x))

domain

f (x) = \frac{2}{9 + 4 x}

x > - \frac{9}{4}

Interval Notation

(- \frac{9}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{9}{4}

Find undefined (singularity) points:

x = - \frac{9}{4}

Combine real regions and undefined points for final function domain

x > - \frac{9}{4}

f (x) = x^{2} ln (\frac{x}{2})

y = 2 x^{2} + 2 x - 4

f (x) = - \frac{5}{x} + 2

- 2 cos (\frac{x}{4}) - 2

4 y = 8 x + 9

What is the domain of f(x)= 2/(sqrt(9+4x)) ?
The domain of f(x)= 2/(sqrt(9+4x)) is x>-9/4