What is the line (2001,17.6),(2002,18.75) ?

The line (2001,17.6),(2002,18.75) is y=1.15x-2283.55

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line (2001,17.6),(2002,18.75)

line

(2001, 17.6), (2002, 18.75)

y = 1.15 x - 2283.55

Solution steps

Find the line

y = mx + b

passing through

(2001, 17.6)

(2002, 18.75)

Compute the slope

(2001, 17.6), (2002, 18.75) : m = 1.15

Compute the

y

intercept:

b = - 2283.55

Construct the line equation

y = mx + b

where

m = 1.15

and

b = - 2283.55

y = 1.15 x - 2283.55

f (x) = \frac{x}{x + 4}

f (x) = 8 - x^{2}

f (x) = \frac{7 x - 2}{x + 9}

f (x) = ∣ x ∣ - 3

4 x - x^{2} + 12

What is the line (2001,17.6),(2002,18.75) ?
The line (2001,17.6),(2002,18.75) is y=1.15x-2283.55