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Popular >

midpoint (2,-1),(4,-3)

Solution

midpoint

(2, - 1), (4, - 3)

Solution

(3, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 1), (x_{2}, y_{2}) = (4, - 3)

= (\frac{4 + 2}{2}, \frac{- 3 - 1}{2})

Refine

= (3, - 2)

Popular Examples

domain of f(x)=10(2x-4)^2+3 domain

f (x) = 10 (2 x - 4)^{2} + 3

domain of f(x)=(x^2-9)/(x^2+6)domain

f (x) = \frac{x ^{2} - 9}{x ^{2} + 6}

critical y=x(x-3)^2 critical points

y = x (x - 3)^{2}

asymptotes of f(x)=(x+4)/(x+3)asymptotes

f (x) = \frac{x + 4}{x + 3}

f (x) = cosh^{2} (x)

Frequently Asked Questions (FAQ)

What is the midpoint (2,-1),(4,-3) ?
The midpoint (2,-1),(4,-3) is (3,-2)