What is the monotone f(x)=2x^2-3x ?

The monotone f(x)=2x^2-3x is Decreasing:-infinity <x< 3/4 ,Increasing: 3/4 <x<infinity

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monotone f(x)=2x^2-3x

monotone intervals

f (x) = 2 x^{2} - 3 x

Decreasing : - \infty < x < \frac{3}{4}, Increasing : \frac{3}{4} < x < \infty

Solution steps

f^{'} (x) = 4 x - 3

Find intervals:

Decreasing

: - \infty < x < \frac{3}{4},

Increasing

: \frac{3}{4} < x < \infty

Decreasing : - \infty < x < \frac{3}{4}, Increasing : \frac{3}{4} < x < \infty

- 2

\frac{5}{2} y = - \frac{7}{9} x

x + 2 y = 5

y = \frac{50 e ^{t}}{2 e ^{t - 1}}

f (x) = 1 - x^{2} - x^{2} - 1

What is the monotone f(x)=2x^2-3x ?
The monotone f(x)=2x^2-3x is Decreasing:-infinity <x< 3/4 ,Increasing: 3/4 <x<infinity