What is the inverse of f(x)=(x-2)/(3x+7) ?

The inverse of f(x)=(x-2)/(3x+7) is (-2-7x)/(3x-1)

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inverse of f(x)=(x-2)/(3x+7)

inverse

f (x) = \frac{x - 2}{3 x + 7}

\frac{- 2 - 7 x}{3 x - 1}

Solution steps

y = \frac{x - 2}{3 x + 7}

Replace

x

with

y

x = \frac{y - 2}{3 y + 7}

Solve for

y, x = \frac{y - 2}{3 y + 7}

\frac{- 2 - 7 x}{3 x - 1}

f (x) = \frac{( x ^{2} + 4 x + 3 )}{x - 1}

f (x) = \frac{x}{( x + 2 ) ( x + 4 )}

f (x) = e^{x}

f (x) = 7 x^{3} + 5 x^{2}

F (t) = \frac{1}{t}

What is the inverse of f(x)=(x-2)/(3x+7) ?
The inverse of f(x)=(x-2)/(3x+7) is (-2-7x)/(3x-1)