What is the extreme f(x)=x^4-8x^3 ?

The extreme f(x)=x^4-8x^3 is Saddle(0,0),Minimum(6,-432)

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extreme f(x)=x^4-8x^3

extreme points

f (x) = x^{4} - 8 x^{3}

Saddle (0, 0), Minimum (6, - 432)

Solution steps

f^{'} (x) = 4 x^{3} - 24 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{4} - 8 x^{3} : 0

Saddle (0, 0)

Plug

x = 6

into

x^{4} - 8 x^{3} : - 432

Minimum (6, - 432)

Saddle (0, 0), Minimum (6, - 432)

f (x) = sin (\frac{1}{4 x - π}) + 2

15 x - 5 y = 20, (9, - 1)

5^{x - 2} + 7

f (x) = - - 2 x - 17

f (x) = 2 - 6 x^{3}

What is the extreme f(x)=x^4-8x^3 ?
The extreme f(x)=x^4-8x^3 is Saddle(0,0),Minimum(6,-432)