What is the perpendicular 15x-5y=20,(9,-1) ?

The perpendicular 15x-5y=20,(9,-1) is y=-1/3 x+2

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perpendicular 15x-5y=20,(9,-1)

perpendicular

15 x - 5 y = 20, (9, - 1)

y = - \frac{1}{3} x + 2

Solution steps

Find the line

y = mx + b

perpendicular to

15 x - 5 y = 20

that passes through

(9, - 1)

Find the slope of

15 x - 5 y = 20 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(9, - 1) : y = - \frac{1}{3} x + 2

y = - \frac{1}{3} x + 2

5^{x - 2} + 7

f (x) = - - 2 x - 17

f (x) = 2 - 6 x^{3}

f (x) = \frac{x + 4}{x - 1}

x^{2} - 2 x

What is the perpendicular 15x-5y=20,(9,-1) ?
The perpendicular 15x-5y=20,(9,-1) is y=-1/3 x+2