What is the inflection f(x)=2x^3-3x^2+8x-4 ?

The inflection f(x)=2x^3-3x^2+8x-4 is (1/2 ,-1/2)

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inflection f(x)=2x^3-3x^2+8x-4

inflection points

f (x) = 2 x^{3} - 3 x^{2} + 8 x - 4

(\frac{1}{2}, - \frac{1}{2})

Solution steps

f^{''} (x) = 12 x - 6

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{3} - 3 x^{2} + 8 x - 4 : - \frac{1}{2}

(\frac{1}{2}, - \frac{1}{2})

f (x) = tan (2 x - 2 π)

y + 3 = 7 (x - 2)

y = x^{2} - 3

x + 4

f (x) = x^{2} - 6

What is the inflection f(x)=2x^3-3x^2+8x-4 ?
The inflection f(x)=2x^3-3x^2+8x-4 is (1/2 ,-1/2)