What is the perpendicular y=3x-2,(2,5) ?

The perpendicular y=3x-2,(2,5) is y=-1/3 x+17/3

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perpendicular y=3x-2,(2,5)

perpendicular

y = 3 x - 2, (2, 5)

y = - \frac{1}{3} x + \frac{17}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 2

that passes through

(2, 5)

Find the slope of

y = 3 x - 2 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(2, 5) : y = - \frac{1}{3} x + \frac{17}{3}

y = - \frac{1}{3} x + \frac{17}{3}

f (x) = 2 - 8 e^{x}

f (x) = y^{4} + x^{3} - 5 x = 0

y = ∣ x ∣ + 2

f (x) = x ln (8 x)

\frac{2 x ^{2} - 5 x + 5}{x - 2}

What is the perpendicular y=3x-2,(2,5) ?
The perpendicular y=3x-2,(2,5) is y=-1/3 x+17/3