What is the inflection f(x)=17x^4-102x^2 ?

The inflection f(x)=17x^4-102x^2 is (-1,-85),(1,-85)

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inflection f(x)=17x^4-102x^2

inflection points

f (x) = 17 x^{4} - 102 x^{2}

(- 1, - 85), (1, - 85)

Solution steps

f^{''} (x) = 204 x^{2} - 204

Find intervals:

Concave Upward

: - \infty < x < - 1,

Concave Downward

: - 1 < x < 1,

Concave Upward

: 1 < x < \infty

Plug

x = - 1

into

17 x^{4} - 102 x^{2} : - 85

(- 1, - 85)

Plug

x = 1

into

17 x^{4} - 102 x^{2} : - 85

(1, - 85)

(- 1, - 85), (1, - 85)

f (x) = - 8 x^{3} + 24 x + 9

\frac{3 ( x - 2 )}{2 ( x - 2 )}

f (x) = - 5 (x + 1)^{2} - 5

x + 18 + 3 x

What is the inflection f(x)=17x^4-102x^2 ?
The inflection f(x)=17x^4-102x^2 is (-1,-85),(1,-85)