extreme f(x)=x^3+12x^2-27x+11

Solução

puntos extremos

f (x) = x^{3} + 12 x^{2} - 27 x + 11

M \overset{a}{ˊ} ximo (- 9, 497), M \overset{ı}{ˊ} nimo (1, - 3)

Passos da solução

f^{'} (x) = 3 x^{2} + 24 x - 27

Find intervals:

Crescente

: - \infty < x < - 9,

Decrescente

: - 9 < x < 1,

Crescente

: 1 < x < \infty

Inserir

x = - 9

x^{3} + 12 x^{2} - 27 x + 11 : 497

M \overset{a}{ˊ} ximo (- 9, 497)

Inserir

x = 1

x^{3} + 12 x^{2} - 27 x + 11 : - 3

M \overset{ı}{ˊ} nimo (1, - 3)

M \overset{a}{ˊ} ximo (- 9, 497), M \overset{ı}{ˊ} nimo (1, - 3)

\frac{x}{x}

m = - \frac{1}{3}, (3, 2)

f (x) = x - \frac{1}{2} x^{2}

y = 6 x^{3} + 8 x^{2} - 5 x + 5

f (x) = \frac{x}{x ^{2} - ∣ x ∣}