What is the extreme f(x)=x^3+12x^2-27x+11 ?

The extreme f(x)=x^3+12x^2-27x+11 is Maximum(-9,497),Minimum(1,-3)

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extreme f(x)=x^3+12x^2-27x+11

extreme points

f (x) = x^{3} + 12 x^{2} - 27 x + 11

Maximum (- 9, 497), Minimum (1, - 3)

Solution steps

f^{'} (x) = 3 x^{2} + 24 x - 27

Find intervals:

Increasing

: - \infty < x < - 9,

Decreasing

: - 9 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 9

into

x^{3} + 12 x^{2} - 27 x + 11 : 497

Maximum (- 9, 497)

Plug

x = 1

into

x^{3} + 12 x^{2} - 27 x + 11 : - 3

Minimum (1, - 3)

Maximum (- 9, 497), Minimum (1, - 3)

\frac{x}{x}

m = - \frac{1}{3}, (3, 2)

f (x) = x - \frac{1}{2} x^{2}

y = 6 x^{3} + 8 x^{2} - 5 x + 5

f (x) = \frac{x}{x ^{2} - ∣ x ∣}

What is the extreme f(x)=x^3+12x^2-27x+11 ?
The extreme f(x)=x^3+12x^2-27x+11 is Maximum(-9,497),Minimum(1,-3)