What is the domain of f(x)=(y+9)/(y^2-9y) ?

The domain of f(x)=(y+9)/(y^2-9y) is y 9

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domain of f(x)=(y+9)/(y^2-9y)

domain

f (x) = \frac{y + 9}{y ^{2} - 9 y}

y < 0 or 0 < y < 9 or y > 9

Interval Notation

(- \infty, 0) \cup (0, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

y = 9, y = 0

The function domain

y < 0 or 0 < y < 9 or y > 9

f (x) = - 6 cos (2 π x) + 3

arctan (x)

\frac{( x - 4 ) ( x - 3 )}{x + 3}

f (x) = \frac{x ^{2} - 2 x - 24}{x - 8}

f (x) = \frac{1}{x} + 2

What is the domain of f(x)=(y+9)/(y^2-9y) ?
The domain of f(x)=(y+9)/(y^2-9y) is y<0\lor 0<y<9\lor y>9