What is the critical 2x^3-3x^2-36x ?

The critical 2x^3-3x^2-36x is x=-2,x=3

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critical 2x^3-3x^2-36x

critical points

2 x^{3} - 3 x^{2} - 36 x

x = - 2, x = 3

Solution steps

2 x^{3} - 3 x^{2} - 36 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 3

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} - 3 x^{2} - 36 x : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 3

x = - 1

x - 1

y = \frac{1}{x ^{2}} - \frac{1}{x}

\frac{x - 2}{x ^{2} - 4}

x^{2} ln (\frac{x}{4})