What is the perpendicular y=(-3)/7 x+4,(9,8) ?

The perpendicular y=(-3)/7 x+4,(9,8) is y= 7/3 x-13

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perpendicular y=(-3)/7 x+4,(9,8)

perpendicular

y = \frac{- 3}{7} x + 4, (9, 8)

y = \frac{7}{3} x - 13

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{- 3}{7} x + 4

that passes through

(9, 8)

Find the slope of

y = \frac{- 3}{7} x + 4 : m = - \frac{3}{7}

Compute the slope of the perpendicular line:

m_{p} = \frac{7}{3}

Find the line with slope m=

\frac{7}{3}

and passing through

(9, 8) : y = \frac{7}{3} x - 13

y = \frac{7}{3} x - 13

y = \frac{2}{3} x

2 + 4^{x - 2}

y = - x + 2

f (x) = 24 x^{3} + \frac{12}{x}

x + 5

What is the perpendicular y=(-3)/7 x+4,(9,8) ?
The perpendicular y=(-3)/7 x+4,(9,8) is y= 7/3 x-13