What is the domain of f(x)= 1/2 sqrt(4+x^2) ?

The domain of f(x)= 1/2 sqrt(4+x^2) is -infinity <x<infinity

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domain of f(x)= 1/2 sqrt(4+x^2)

domain

f (x) = \frac{1}{2} 4 + x^{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

(- 1.7) (0.8)

f (x) = x^{3} - 12 x + 1

3 x - y = - 2

f (x) = \frac{1}{x ^{2} - 3 x - 4}

f (x) = \frac{3 x}{x + 5}

What is the domain of f(x)= 1/2 sqrt(4+x^2) ?
The domain of f(x)= 1/2 sqrt(4+x^2) is -infinity <x<infinity