What is the domain of 1/(x^2+x+3) ?

The domain of 1/(x^2+x+3) is -infinity <x<infinity

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domain of 1/(x^2+x+3)

domain

\frac{1}{x ^{2} + x + 3}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{4 x}{x + 4}

x + 3 y = 8

18 x + 15 y = - 90

y = 2 x + 4

- 6 cos (x)

What is the domain of 1/(x^2+x+3) ?
The domain of 1/(x^2+x+3) is -infinity <x<infinity