What is the critical f(x)=x^4-12x^3+40x^2 ?

The critical f(x)=x^4-12x^3+40x^2 is x=0,x=4,x=5

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critical f(x)=x^4-12x^3+40x^2

critical points

f (x) = x^{4} - 12 x^{3} + 40 x^{2}

x = 0, x = 4, x = 5

Solution steps

x^{4} - 12 x^{3} + 40 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4, x = 5

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 12 x^{3} + 40 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 4, x = 5

f (x) = 3 x^{2} - 7

(x - 4)^{2}

f (x) = x^{2}

f (x) = \frac{3 x ^{2} - 8}{x + 2}

f (x) = x^{4} - 34 x^{2} - 72

What is the critical f(x)=x^4-12x^3+40x^2 ?
The critical f(x)=x^4-12x^3+40x^2 is x=0,x=4,x=5