What is the domain of f(x)=(2x)/(16-x^2) ?

The domain of f(x)=(2x)/(16-x^2) is x 4

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domain of f(x)=(2x)/(16-x^2)

domain

f (x) = \frac{2 x}{16 - x ^{2}}

x < - 4 or - 4 < x < 4 or x > 4

Solution steps

Find undefined (singularity) points:

x = 4, x = - 4

The function domain

x < - 4 or - 4 < x < 4 or x > 4

f (x) = 4 e^{x}

f (x) = ∣ x + 2 ∣ - 1

f (x) = \frac{6 x}{x ^{2} + 1}

(6, 19.1), (7, 19.8)

f (x) = - lo g_{4} (x + 4) - 6

What is the domain of f(x)=(2x)/(16-x^2) ?
The domain of f(x)=(2x)/(16-x^2) is x<-4\lor-4<x<4\lor x>4