What is the perpendicular 2x+7y+4=0 ?

The perpendicular 2x+7y+4=0 is y= 7/2 x+b

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perpendicular 2x+7y+4=0

perpendicular

2 x + 7 y + 4 = 0

y = \frac{7}{2} x + b

Solution steps

Find the slope of

2 x + 7 y + 4 = 0 : m = - \frac{2}{7}

Compute the slope of the perpendicular line:

m_{p} = \frac{7}{2}

Line with slope m=

\frac{7}{2} : y = \frac{7}{2} x + b

y = \frac{7}{2} x + b

\frac{5}{6}

x + 2 y = 3

3 - t - 2 + t

1 - 9 x - 6 x^{2} - x^{3}

x + 11