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Popular >

range of f(x)=x^2+6x-8

Solution

range

f (x) = x^{2} + 6 x - 8

Solution

f (x) \geq - 17

+1

Interval Notation

[- 17, \infty)

Solution steps

Vertex of

x^{2} + 6 x - 8 :

Minimum

(- 3, - 17)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 3, - 17)

f (x) \geq - 17

Popular Examples

domain of f(x)=sin^2(x)domain

f (x) = sin^{2} (x)

intercepts of y= 1/4 x intercepts

y = \frac{1}{4} x

critical x^2-4x+3 critical points

x^{2} - 4 x + 3

domain of f(x,y)=sin((x-3)/(x-5))domain

f (x, y) = sin (\frac{x - 3}{x - 5})

inverse of f(x)= 5/(x^2+1)inverse

f (x) = \frac{5}{x ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+6x-8 ?
The range of f(x)=x^2+6x-8 is f(x)>=-17