What is the asymptotes of f(x)=((x^2-1))/(2x^2-x-3) ?

The asymptotes of f(x)=((x^2-1))/(2x^2-x-3) is Vertical: x= 3/2 ,Horizontal: y= 1/2

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asymptotes of f(x)=((x^2-1))/(2x^2-x-3)

asymptotes

f (x) = \frac{( x ^{2} - 1 )}{2 x ^{2} - x - 3}

Vertical : x = \frac{3}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 1}{2 x ^{2} - x - 3} : x = \frac{3}{2}

Horizontal Asymptotes of

\frac{x ^{2} - 1}{2 x ^{2} - x - 3} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 1}{2 x ^{2} - x - 3} :

None

Vertical : x = \frac{3}{2}, Horizontal : y = \frac{1}{2}

0. 3^{x}

f (x) = 1 + (4 + x)^{\frac{1}{2}}

f (x) = \frac{2 x - 6}{x}

f (x) = x - 1

f (x) = \frac{1}{x + 7}

What is the asymptotes of f(x)=((x^2-1))/(2x^2-x-3) ?
The asymptotes of f(x)=((x^2-1))/(2x^2-x-3) is Vertical: x= 3/2 ,Horizontal: y= 1/2