What is the inverse of f(x)=x-5x^2 ?

The inverse of f(x)=x-5x^2 is -(-1+sqrt(1-20x))/(10),-(-1-sqrt(1-20x))/(10)

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inverse of f(x)=x-5x^2

inverse

f (x) = x - 5 x^{2}

- \frac{- 1 + 1 - 20 x}{10}, - \frac{- 1 - 1 - 20 x}{10}

Solution steps

y = x - 5 x^{2}

Replace

x

with

y

x = y - 5 y^{2}

Solve for

y, x = y - 5 y^{2}

- \frac{- 1 + 1 - 20 x}{10}, - \frac{- 1 - 1 - 20 x}{10}

m = - \frac{3}{2}, (- 5, 0)

x (x + 3)

f (x) = x^{4} + 8 x^{2} + 16

\frac{1}{4} x^{2} - \frac{5}{2} x + \frac{13}{4}

f (x) = \frac{- 3}{x}

What is the inverse of f(x)=x-5x^2 ?
The inverse of f(x)=x-5x^2 is -(-1+sqrt(1-20x))/(10),-(-1-sqrt(1-20x))/(10)