en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=(x-1)^2-2

Solution

range

f (x) = (x - 1)^{2} - 2

Solution

f (x) \geq - 2

+1

Solution steps

Vertex of

(x - 1)^{2} - 2 :

Minimum

(1, - 2)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (1, - 2)

f (x) \geq - 2

Popular Examples

inverse of f(x)=(x+3)/(2x-1)inverse

f (x) = \frac{x + 3}{2 x - 1}

inverse of sqrt(6x+24)inverse

6 x + 24

domain of ln(x^3+x^2-2x)domain

ln (x^{3} + x^{2} - 2 x)

inverse of f(x)=9+sqrt(4+x)inverse

f (x) = 9 + 4 + x

domain of f(x)=3-2x-x^2 domain

f (x) = 3 - 2 x - x^{2}

Frequently Asked Questions (FAQ)

What is the range of f(x)=(x-1)^2-2 ?
The range of f(x)=(x-1)^2-2 is f(x)>=-2