What is the domain of f(x)=sqrt(x^2+2x) ?

The domain of f(x)=sqrt(x^2+2x) is x = 0

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domain of f(x)=sqrt(x^2+2x)

domain

f (x) = x^{2} + 2 x

x \leq - 2 or x \geq 0

Interval Notation

(- \infty, - 2] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 0

The function domain

x \leq - 2 or x \geq 0

y - 5 = - 2 (x + 5)

(\frac{2}{3})^{x} + 2

y = - 10 x - 3

f (x) = \frac{4 x - 1}{2}

(- 1, 6), (- 1, - 2)

What is the domain of f(x)=sqrt(x^2+2x) ?
The domain of f(x)=sqrt(x^2+2x) is x<=-2\lor x>= 0