What is the domain of f(x)=(sqrt(x-2))^2+3 ?

The domain of f(x)=(sqrt(x-2))^2+3 is x>= 2

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domain of f(x)=(sqrt(x-2))^2+3

domain

f (x) = (x - 2)^{2} + 3

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

x^{3} + 9

f (x) = \frac{3}{1 - e ^{x}}

3 x^{2} - 2 x - 6

3 (\frac{1}{2})^{x}

f (x) = \frac{1 + 2 x}{x ^{2} + 1}

What is the domain of f(x)=(sqrt(x-2))^2+3 ?
The domain of f(x)=(sqrt(x-2))^2+3 is x>= 2