What is the critical f(x)=x^3-3x^2+3x-7 ?

The critical f(x)=x^3-3x^2+3x-7 is x=1

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critical f(x)=x^3-3x^2+3x-7

critical points

f (x) = x^{3} - 3 x^{2} + 3 x - 7

x = 1

Solution steps

x^{3} - 3 x^{2} + 3 x - 7

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 3 x^{2} + 3 x - 7 : - \infty < x < \infty

All critical points are in domain

x = 1

f (x) = \frac{x + 3}{x - 1}

f (x) = 4 sin (2 x - \frac{π}{6}) + 2

x^{2} - 3 x

f (x) = \frac{8 x + 3}{7 x + 9}

f (x) = \frac{( x - 10 ) ^{3}}{10} + 5

What is the critical f(x)=x^3-3x^2+3x-7 ?
The critical f(x)=x^3-3x^2+3x-7 is x=1