What is the shift-(cos(pi(11x)/6))/(2)-2 ?

The shift-(cos(pi(11x)/6))/(2)-2 is Phase:0, Vertical:-2

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shift-(cos(pi(11x)/6))/(2)-2

shift

- \frac{cos ( π \frac{11 x}{6} )}{2} - 2

Phase : 0, Vertical : - 2

Solution steps

Simplify

- \frac{cos ( π \frac{11 x}{6} )}{2} - 2 : - \frac{cos ( \frac{11 π x}{6} )}{2} - 2

f (x) = - \frac{cos ( \frac{11 π x}{6} )}{2} - 2

g (B x - C) = cos (\frac{11 π x}{6}), B = \frac{11 π}{6}, C = 0, D = - 2

Therefore, the phase shift

\frac{C}{B}

\frac{0}{\frac{11 π}{6}}

0

The vertical shift

D

- 2

- 2

f (x) = \frac{1}{9 - t}

\frac{( x + 2 ) ^{2}}{x - 1}

csc (\frac{π}{3} x + π)

y = lo g_{3} (x)

f (x) = x^{4}

What is the shift-(cos(pi(11x)/6))/(2)-2 ?
The shift-(cos(pi(11x)/6))/(2)-2 is Phase:0, Vertical:-2