What is the domain of f(x)= 1/(sqrt(x+6)) ?

The domain of f(x)= 1/(sqrt(x+6)) is x>-6

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domain of f(x)= 1/(sqrt(x+6))

domain

f (x) = \frac{1}{x + 6}

x > - 6

Interval Notation

(- 6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = - 6

Combine real regions and undefined points for final function domain

x > - 6

f (x) = 2 x^{2} - 4 x - 5

f (x) = lo g_{2} (x + 5) - 9

f (x) = 2 (x - 3)^{2}

f (x) = - \frac{2 x}{x - 1}

5 x - 3

What is the domain of f(x)= 1/(sqrt(x+6)) ?
The domain of f(x)= 1/(sqrt(x+6)) is x>-6