What is the critical f(x)=8x^3-x^4 ?

The critical f(x)=8x^3-x^4 is x=0,x=6

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critical f(x)=8x^3-x^4

critical points

f (x) = 8 x^{3} - x^{4}

x = 0, x = 6

Solution steps

8 x^{3} - x^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 6

Identify critical points not in

f (x)

domain

Domain of

8 x^{3} - x^{4} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 6

\frac{3}{2}

\frac{x}{( \frac{3}{2} )} + \frac{y}{- 7} = 1

y = - 5 x + 6

2.55 x - y + 163.75

f, f > x + 5