What is the critical f(x)=x^3+6x^2-15x ?

The critical f(x)=x^3+6x^2-15x is x=-5,x=1

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critical f(x)=x^3+6x^2-15x

critical points

f (x) = x^{3} + 6 x^{2} - 15 x

x = - 5, x = 1

Solution steps

x^{3} + 6 x^{2} - 15 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{3} + 6 x^{2} - 15 x : - \infty < x < \infty

All critical points are in domain

x = - 5, x = 1

x + 2 - 6

f (x) = 5 x^{2} - 20 x + 2

f (x) = 3 x - y = - 3

f (x) = \frac{( 6 x - 1 )}{2 x + 5}

4 x + 10 y = - 20

What is the critical f(x)=x^3+6x^2-15x ?
The critical f(x)=x^3+6x^2-15x is x=-5,x=1