What is the domain of f(x)=(sqrt(9+x))/(2-x) ?

The domain of f(x)=(sqrt(9+x))/(2-x) is -9 2

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domain of f(x)=(sqrt(9+x))/(2-x)

domain

f (x) = \frac{9 + x}{2 - x}

- 9 \leq x < 2 or x > 2

Interval Notation

[- 9, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 9 \leq x < 2 or x > 2

f (x) = 5 tan (x + \frac{π}{2})

\frac{x}{5 + x ^{2}}

f (x) = - x^{4} + 6 x^{2}

f (x) = \frac{4 ^{y}}{4}

f (x) = - 4 (x - 2)^{2} (x^{2} - 9)

What is the domain of f(x)=(sqrt(9+x))/(2-x) ?
The domain of f(x)=(sqrt(9+x))/(2-x) is -9<= x<2\lor x>2