What is the inverse of f(x)=5-2x^2 ?

The inverse of f(x)=5-2x^2 is sqrt(-(x-5)/2),-sqrt(-(x-5)/2)

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inverse of f(x)=5-2x^2

inverse

f (x) = 5 - 2 x^{2}

- \frac{x - 5}{2}, - - \frac{x - 5}{2}

Solution steps

y = 5 - 2 x^{2}

Replace

x

with

y

x = 5 - 2 y^{2}

Solve for

y, x = 5 - 2 y^{2}

- \frac{x - 5}{2}, - - \frac{x - 5}{2}

\frac{1}{1 - x ^{n}}

f (x) = \frac{3}{5} x + \frac{1}{3}

f (x) = x^{10}

ln (4) + ln (x)

f (x) = \frac{5 x ^{2}}{x ^{2} - 1}

What is the inverse of f(x)=5-2x^2 ?
The inverse of f(x)=5-2x^2 is sqrt(-(x-5)/2),-sqrt(-(x-5)/2)