What is the asymptotes of g(t)=(16)/(1+3^{-t)} ?

The asymptotes of g(t)=(16)/(1+3^{-t)} is Horizontal: y=16,y=0

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asymptotes of g(t)=(16)/(1+3^{-t)}

asymptotes

g (t) = \frac{16}{1 + 3 ^{- t}}

Horizontal : y = 16, y = 0

Solution steps

Vertical asymptotes of

\frac{16}{1 + 3 ^{- t}} :

None

Horizontal Asymptotes of

\frac{16}{1 + 3 ^{- t}} : y = 16, y = 0

Slant Asymptotes of

\frac{16}{1 + 3 ^{- t}} :

None

Horizontal : y = 16, y = 0

\frac{3 x + 4}{6 x + 1}

f (x) = (x^{2} - 2 x - 8)^{\frac{1}{3}}

f (x) = x + 3

y = - x + 1 - 3

f (x) = \frac{5 x ( x - 6 )}{5 x ^{2} - 29 x - 6}

What is the asymptotes of g(t)=(16)/(1+3^{-t)} ?
The asymptotes of g(t)=(16)/(1+3^{-t)} is Horizontal: y=16,y=0